how to get only 3 digit under point
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octopus_love on 11 Sep 2017
I want to get the only 3 digit under the point. For example,
a = 123.4567;
and I want to get just modify_a = 123.456. I tried the code
a = round(a*10^3)/10^3
but the result is , a = 123.457 0;
How can I remove the '0' point? please help me.
Thank you in advance.
Image Analyst on 11 Sep 2017
Edited: Image Analyst on 11 Sep 2017
Use round() and pass in the number of digits as the second input:
a3 = round(a, 3)
Keep in mind that it's still a 64 bit number but it will be rounded and all of the umpteen digits after the third decimal place will be 0. They will still be there (you can't get rid of them), but they will be zero. You can then print out that number with fprintf() or sprintf() with 1,2,3,4,5 or however many decimal places you want, and you will see however many you told it to print, just keep in mind that any digits after 3 will be 0.
fprintf('%.3f', a); % Shows n.nnn
fprintf('%.6f', a); % Shows n.nnn000
fprintf('%.1f', a); % Shows n.n
More Answers (1)
Walter Roberson on 11 Sep 2017
In order to do that you will need to override the important internal routine toolbox/matlab/lang/@double/display to implement an additional "format" that has exactly three decimal places and which truncates. I would expect that would be a notable amount of work to get right without interfering with any of the current uses of the routine.
The built in "format" can display 2 digits after the decimal place ("format bank" or sometimes "format short g") or 4 digits after the decimal place ("format short" or "format short eng"), or 15 digits after the decimal place ("format long"), or up to 15 digits after the decimal place, stopping the remaining digits of the 15 are all 0. The "format" routines all round.
For any other format like 3 digits exactly with truncation, you need to override the display method. Or you could do the display formatting yourself, using sprintf() or fprintf()