converting uint32 to cell

after operating the command

         c4 = transpose( [ arrayl{:,4} ] );

in a matrix , c4 returns a columns of numbers (for more, refer to http://www.mathworks.in/matlabcentral/answers/35528-reading-numbers-from-an-unknown-format)

but the output is in uint32 format and i need to get it converted to cell format , suggestions please

Answer 1

[Walter Roberson]

array1(:,4)

seems to be what you are describing.

Answer 2

[Jan]

This:

[ arrayl{:,4} ]

converts the elements of the 4th column of the cell array1 explicitly to a vector. If you do not want this conversion, omit it:

c4 = transpose(arrayl(:,4));

Or if you want a {Nx1} cell, see Walter's suggestion.

[Karan]

thanx both of you , i was utterly confused with the other columns of the matrix many of differet types , some string some uint32 some text ....