Vectorization

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Aravin
Aravin am 15 Apr. 2012
Dear Community,
Let say I have Matrix M. In Matrix M, each Column is feature of Image. Now what I want to get a binary matrix B by following way.
for given image feature i:
B(1,i) = M(1,i) >= M(2,i);
its mean for each image feature, each cell is compared to its next cell. I want to do it without loops for speed.
  1 Kommentar
Oleg Komarov
Oleg Komarov am 15 Apr. 2012
"Without loops for speed" is really not the right statement anymore.
Many times loops are much faster is correctly set up.

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Oleg Komarov
Oleg Komarov am 15 Apr. 2012

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Jan
Jan am 15 Apr. 2012
B = (M(1:end-1, :) >= M(2:end, :));
  2 Kommentare
Jan
Jan am 15 Apr. 2012
It is worth to investigate the similarities and differences to Oleg's (faster) solution.
Aravin
Aravin am 18 Apr. 2012
Jan, Oleg worked on my small examples. I could find any dissimilarity. If you have in your mind then please share.
Thanks for your help too.

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