How to get the smallest difference(Array)

>>The issue i'm having is that if there are two values of equal difference only the closest one is displayed. Can someone please correct my coding.
function[smallestPosition] = FindSmallestElevationChange(i,B)
E = [ 3 6 5 4 7 8 3 ; 5 7 6 2 3 1 7 ; 6 8 5 8 5 4 8 ; 7 4 9 7 6 5 3 ];
*%B = 3 adjacent values e.g.. if I chose E(10), B = [ 4 2 8 ]
%the smallest difference should be 4 and 8 which is (1 and 3) respectively
%since there is a difference of 2 for both of them.*
E(i);
[c index] = min(abs(B-E(i)));
the output given is only 1(which is 4)
[REVERTED, was edited away by the OP, Jan]

7 Kommentare

KSSV
KSSV am 31 Aug. 2017
Please not that....._min_ gives you only minimum value....so output is only one value. What you are expecting?
KL
KL am 31 Aug. 2017
What's the point of uploading that picture? You expect us to read it this way?
José-Luis
José-Luis am 31 Aug. 2017
Where on god's green earth is abs(10-8) equal to abs(10-4)?
Let me rephrase. Unless something very basic has changed, there is no way that
2 == 4
You probably meant E(6) (just dawned on me, I need coffee). If that's the case, my answer should solve your problem.
José-Luis
José-Luis am 31 Aug. 2017
Well then I don't understand what you are trying to achieve.
Cedric
Cedric am 17 Sep. 2017
Bearbeitet: Cedric am 17 Sep. 2017
Shivam Prasad, the least you can do if you don't need help anymore, is to accept the answer of whoever was nice enough to give you freely part of his/her time.
I accepted the answer from José-Luis (before Jan restored the original question and answered).
The question was originally titled "How to get the smallest difference(Array)" and it had the following picture attached:
Jan
Jan am 17 Sep. 2017
Bearbeitet: Jan am 17 Sep. 2017
I have reverted the question. Please, Shivam Prasad, do not remove the question after somebody has spent the time to provide an answer.

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 Akzeptierte Antwort

José-Luis
José-Luis am 31 Aug. 2017

0 Stimmen

bla = randi(50,10);
val = 25;
result = abs(bla-val);
result = result == min(result(:));
[xx,yy] = ndgrid(1:size(bla,1),1:size(bla,2));
idx_x = xx(result)
idx_y = yy(result)

Weitere Antworten (1)

Jan
Jan am 17 Sep. 2017
Bearbeitet: Jan am 17 Sep. 2017

1 Stimme

The question does not contain the detail, that the input is a matrix, but a scalar and a vector only. Then:
[c, index] = min(abs(Vec - E));
is almost a solution. Do it in two steps:
Dist = abs(Vec - E);
and then use this to determine the indices:
Dist == min(Dist)

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