how to find index of the point in matrix with condition?

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ha ha
ha ha am 28 Aug. 2017
Kommentiert: Quincy Sproul am 20 Nov. 2022
Let's say, i have matrix 6-by-1 matrix:
A=[ 1 --->labelling "1"
6 --->labelling "2"
3 --->labelling "3"
5 --->labelling "4"
-3 --->labelling "5"
10 ] --->labelling "6"
and
B=[5]
I want to write the code to compare each value in matrix A with B with condition ( If {A}<B---> I will pick up the index and the value from matrix A to make a new matrix)
Particurly: I have the number 1,3, -3 (in matrix A) is smaller than 5 (in matrix B) so I will have the result after compare condition as follows:
C=[ 1 --->labelling "1"
3 --->labelling "3"
-3 ] --->labelling "5"
and the labelling matrix D will be :
D=[ 1
3
5 ]
How to write a relationship between matrix A,B,C,D ?
  2 Kommentare
KL
KL am 28 Aug. 2017
Read the documentation. Your questions have direct and simple answers right there.
Quincy Sproul
Quincy Sproul am 20 Nov. 2022
yeh read the entire documentation for a single question.

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Benjamin Imbach
Benjamin Imbach am 28 Aug. 2017
Bearbeitet: Benjamin Imbach am 28 Aug. 2017
check out the find function.
A = [1 6 3 5 -3 10]';
B = 5;
D = find(A<B); %(linear index)
C = A(D);
  1 Kommentar
Jan
Jan am 28 Aug. 2017
Bearbeitet: Jan am 28 Aug. 2017
This is even more efficient with "logical indexing": omit the "find".
C = A(A < B)

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