How to calculate maximum up to current point?

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Steven Niggebrugge
Steven Niggebrugge am 18 Aug. 2017
Kommentiert: John D'Errico am 18 Aug. 2017
Hi, how can i calculate the an array of current maxima, i.e. for each point in the array to calculate the maximum from the first observation of the array to the current? e.g. for array [3 8 10 6] i want the output to be [3 8 10 6] ?
Is there a function to do this (movmax i think it works for a fixed lookback or lookforward) or do i just need to loop through all observations?
  2 Kommentare
José-Luis
José-Luis am 18 Aug. 2017
You probably meant [3,8,10,10] as your result.
Steven Niggebrugge
Steven Niggebrugge am 18 Aug. 2017
yes indeed, thanks very much!

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Antworten (2)

John D'Errico
John D'Errico am 18 Aug. 2017
cummax([3 8 10 6])
ans =
3 8 10 10
  2 Kommentare
José-Luis
José-Luis am 18 Aug. 2017
Bearbeitet: José-Luis am 18 Aug. 2017
+1
Whenever I think of a tortured way, there's a built-in function. It is hard to keep up.
John D'Errico
John D'Errico am 18 Aug. 2017
I keep learning new things on Answers. New little goodies that appeared when I was not watching. I guess we all should read the release notes religiously. That would take all the fun out of it though. :)

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José-Luis
José-Luis am 18 Aug. 2017
a = [3,8,10,6,5,11,12,-20];
n = numel(a);
result = tril(bsxfun(@minus,a,a'));
[~,idx] = max(result,[],2);
result = a(idx)

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