Splitting a table to 2

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Rafi Kandli
Rafi Kandli am 16 Aug. 2017
Kommentiert: KL am 16 Aug. 2017
Hello all, I have a table named A. I want to split it into 2 sub-tables: Table 1 has 60% of the rows in A, chosen randomly. Table 2 has all the other rows that are not in table 1. Any elegant idea on how to do this?

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KL
KL am 16 Aug. 2017
dummy = 10*rand(10,4);
T = array2table(dummy)
ranRows = randperm(length(dummy));
T1 = T(ranRows(1:(0.6*length(dummy))),:)
T2 = T(ranRows((0.6*length(dummy))+1:end),:)
  2 Kommentare
Guillaume
Guillaume am 16 Aug. 2017
The proper function for getting the height of a table is height, so:
ranrows = randperm(height(T));
T1 = T(ranRows(1:0.6*height(T)), :);
T2 = T(ranRows(0.6*height(T)+1:end), :);
To avoid a warning, I would also wrap the 0.6*height(T) calculation inside a ceil, a floor or a round.
KL
KL am 16 Aug. 2017
Thanks Guillaume!

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Adrian
Adrian am 16 Aug. 2017
Bearbeitet: Adrian am 16 Aug. 2017
Note that this will only play nicely if you have a reasonably large array.
selection = randi([1 10], size(A,1),1)
A_sixty = A(selection>4);
A_forty = A(selection<=4);

Sean de Wolski
Sean de Wolski am 16 Aug. 2017
If you're looking to split your data into a training and testing set, then it might pay to look at cvpartition as well, it provides more options for splitting tables.

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