Addressing folder with varying name of in a path

Hello, In below code:

   s_root='C:\datasets\dataset_Experiment1\segments_all\Asphyxia\SHL-M-F-
   0293\file';
   s_infants=dir([s_root '*']);

    .
    .
    .

The folders of Asphyxia and SHL-M-F-0293 will have different name in each run. How should I address the varying name of these folders which are within the path? Thanks

Answer 1

[Jos (10584)]

Take a look at the function FULLFILE. This may get you started.

folders = {'AAA','BBB'} % brows for files
for k=1:numel(folders),
  CurrentFolder = fullfile('C:','basefolder',folders{k},'data')
  FileStr = fullfile(CurrentFolder,'*.txt') 
  dir (FileStr)
end

[Shaya s]

Thanks. But I don't understand what is the first line for? And it should address the folder, not .txt file.

Answer 2

[Jan]

With modern Matlab versions:

pattern  = ['C:\datasets\dataset_Experiment1\segments_all\**\file';
FileList = dir(pattern);
FileName = fullfile({FileList.folder}, {FileList.name});

Afterwards you can use regexp to apply the pattern '\*Asphyxia*\*SHL-M-F-0293*\'.

I cannot test this currently due to the lack of a modern Matlab version.

[EDITED] There are many recursive dir versions in the FileExchange: https://www.mathworks.com/matlabcentral/fileexchange/?utf8=%E2%9C%93&term=recursive+dir, bu no one helps to resolve pattern like:

'C:\datasets\*Asphyxia*\*SHL-M-F-0293*\file\*.*'

But it is not hard to implement this:

Pattern  = 'C:\datasets\*Asphyxia*\*SHL-M-F-0293*\file\*.*';

Pattern  = strrep(Pattern, '/', '\');  % Consider unix
PatternC = splitstr(Pattern, '\');
FileList = {''};
for iP = 1:numel(PatternC)
  part = PatternC{iP}
  if any(part == '*') || any(part == '?')
    newFileList = cell(1, numel(FileList));
    for iFile = 1:numel(FileList)
      DirList = dir(fullfile(FileList{iFile}, part));
      if ~isempty(DirList)
        newFileList{iFile} = fullfile({DirList.folder}, {DirList.name});
      end
    end
    FileList = cat(2, newFileList{:});
  else  % No pattern, append string:
    FileList = fullfile(FileList, part));
  end
end

UNTESTED! I do not have a modern Matlab currently and cannot test this!!!

[Shaya s]

It doesn't result. Maybe I do make mistake! I should add, that in the path: s_root='C:\datasets\dataset_Experiment1\segments_all\*Asphyxia*\*SHL-M-F-0293\file*';

There's no stars surrounding the folder names, actually they were creating while I was balding them while writing here! So the correct is: s_root='C:\datasets\dataset_Experiment1\segments_all\Asphyxia\SHL-M-F- 0293\file';

[Jan]

@Shaya S: What a pitty. Then my code is completely rubbish.

Okay. Restart. What exactly is varying in the path name? What do you want as result?

[Shaya s]

Sorry my English is bad for a clear explanation. Please consider this address:

s_root='C:\datasets\dataset_Experiment1\segments_all\Asphyxia\SHL-M-F-0293\file';

Its a part of script for doing an instruction. I also have a query script in which I give the name of disease to it. When it runs the name of folder "Asphyxia" and "SHL-M-F-0293" will change according to the disease name. I don't know how to address now the new changing path.

[Jan]

If the part "Asphyxia" is changed, you need to find out, how you can identify the new folder. If the "segments_all" folder contains an arbitrary number of folders and you do not have any additional information about which folder you should choose, then your problem cannot be solved. The same for "SHL-M-F-0293". Please explain how you would choose the wanted folder manually. Perhaps it is the newest folder, or the only folder. Currently you did not give us enough information to solve the problem.

[Shaya s]

One had helped me which works:

   dataset_seg_path='C:\dataset_tests\dataset_Experiment1\segments_all';

   d = dir(dataset_seg_path);

    for i=3:numel(d)

    if(d(i).isdir)
        dataset_classes_path = fullfile(dataset_seg_path, d(i).name);

    end

   end

Thank you for your attention