datestr problem with minutes

Hello everyone,
I'm encountering a problem with date conversion. I have a dataset column with dates in '1/5/2017 12:10:00AM' form and I want to convert it into '2017-05-01 00:10:00' format. I used the datestr function but the minutes are incorrect. All rows return with 00 minutes.
How can I fix this?
Thank you in advance, Vanessa

3 Kommentare

Stephen23
Stephen23 am 29 Jun. 2017
@Vanessa: please show us the code you have used and the data that causes this behavior.
Vanessa
Vanessa am 29 Jun. 2017
kwhm.date=datestr(kwhm.date,'yyyy-mm-dd HH:MM:SS');
date '1/5/2017 12:10:00AM' '1/5/2017 12:15:00AM' '1/5/2017 12:20:00AM' etc
Andrei Bobrov
Andrei Bobrov am 29 Jun. 2017
Dear Vanessa! please accept the answers that solved your problems.

Melden Sie sich an, um zu kommentieren.

Antworten (2)

Walter Roberson
Walter Roberson am 29 Jun. 2017

0 Stimmen

t = datenum('1/5/2017 12:10:00AM' );
datestr(t, 'YYYY-mm-DD HH:MM:ss')
Andrei Bobrov
Andrei Bobrov am 29 Jun. 2017
Bearbeitet: Andrei Bobrov am 29 Jun. 2017

0 Stimmen

a = datetime('1/5/2017 12:10:00AM','I','dd/MM/yyyy hh:mm:ssa','F','yyyy-MM-dd HH:mm:ss')

4 Kommentare

Vanessa
Vanessa am 29 Jun. 2017
Thanks this worked but I have some rows which are '1/5/2017' without the time and the result of the above function is NaT. How can overcome this? thanks
You cannot. When you use datetime() all of the entries need to be in the same 'InputFormat' (that here was abbreviated as 'I'). If you know you have entries that are in a different format, you need to detect and process them.
For example:
a = datetime(StringArrayOfTimes, 'I', 'dd/MM/yyyy hh:mm:ssa','F','yyyy-MM-dd HH:mm:ss');
failed_on = isnat(a);
a(failed_on) = datetime(StringArrayOfTimes(failed_on), 'I', 'dd/MM/yyyy', 'F', 'yyyy-MM-dd HH:mm:ss');
The above does a patch-up pass, where it tries to re-interpret the failed times with the abbreviated format.
Vanessa
Vanessa am 29 Jun. 2017
Thank you very much!!!
a = {'1/5/2017';
'1/5/2017 12:10:00AM';
'1/5/2017 12:15:00AM';
'1/5/2017 12:20:00AM';
'2/5/2017'};
t = ~cellfun(@isempty,regexp(a,'\d{4}$'));
a(t) = cellfun(@(x)[x,' 00:00:00AM'],a(t),'un',0);
out = datetime(a,'I','dd/MM/yyyy hh:mm:ssa','F','yyyy-MM-dd HH:mm:ss')

Melden Sie sich an, um zu kommentieren.

Kategorien

Tags

Gefragt:

am 29 Jun. 2017

Kommentiert:

am 29 Jun. 2017

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by