theta and miu are constants
theta = 0.01305
miu = 0.0546
const = @(x) tan(theta + miu)
r = integral(constant,0,1)

1 Kommentar

Jan
Jan am 29 Jun. 2017
The integral of a constant function is the size of the rectangle between the curve and the X axis: const * (1 - 0).

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Joshua
Joshua am 29 Jun. 2017
Bearbeitet: Torsten am 21 Nov. 2022

3 Stimmen

theta = 0.01305
theta = 0.0131
miu = 0.0546
miu = 0.0546
const = @(x) tan(theta + miu)+0*x
const = function_handle with value:
@(x)tan(theta+miu)+0*x
r = integral(const,0,1)
r = 0.0678

2 Kommentare

Yianni Koumarnetos
Yianni Koumarnetos am 21 Nov. 2022
I am doing this and it is telling me that the integral is an error.
Torsten
Torsten am 21 Nov. 2022
Bearbeitet: Torsten am 21 Nov. 2022
Don't forget the +0*x when integrating your constant function.
Or use
theta = 0.01305
theta = 0.0131
miu = 0.0546
miu = 0.0546
const = @(x) tan(theta + miu)
const = function_handle with value:
@(x)tan(theta+miu)
r = integral(const,0,1,'ArrayValued',true)
r = 0.0678

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Gefragt:

am 29 Jun. 2017

Bearbeitet:

am 21 Nov. 2022

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