Finding similar values in two different cell arrays and comparing them?

I have 2 separate cell arrays (alight and board), both containing a column for name, hour, and passenger count. I need to find where the name and hour is equal to each other in both columns, and take the corresponding passenger count of both and then find the difference in passenger count. That difference should then be stored in another column in either one of the cell arrays. This is my code but it has an "too many input arguments" and "error using ==" error in line "index = find(board{:,1} == stn & board{:,2} == hour);". Can someone help me out? Thanks in advance.

 for i = 1:size(alight,1)

    stn = alight{i,1}; % stn name (string)
    hour = alight{i,2}; % hour (number)  
    pax_alight = alight{i,3}; % count (number)

    index = find(board{:,1} == stn & board{:,2} == hour);

    if isempty(index) 
        pax_board = 0;
    else 
        pax_board = board{index,3};
    end

    net = pax_alight - pax_board;
    alight(i,4) = net;
end

Answer 1

[Akira Agata]

I would recommend using table to store the data and innerjoin function to find the corresponding passengers. Here is a simple example.

 % Test data
 alight = table({'Smith';'Johnson';'Williams'},[10;20;30],[40;50;60],...
    'VariableNames',{'Name','Hours','Count'});
 board = table({'Johnson';'Lucy';'Smith'},[20;50;30],[5;10;15],...
    'VariableNames',{'Name','Hours','Count'});

 % Find the corresponding data, and store the result to alight.Net column
 % (in this case, only Johnson matches.)
 [~, ia, ib] = innerjoin(alight, board, 'Keys', [1 2]);
 alight.Net = alight.Count;
 alight.Net(ia) = alight.Net(ia) - board.Count(ib);

Answer 2

[Jan]

The failing line can be replaced by:

index = find(strcmp(board(:,1).', stn) & [board{:,2}] == hour);