Finding zeros of an equation

How do you find all zeros of an equation?
I have this problem and I'm suppose to find all the zeros of 3x^3 - 12x^2 - 33x + 80 over the range -10< x <10. I graphed it on my calculator and it clearly crosses the x-axis 3 times over -10 < x < 10.
When I do the problem in matlab it only gives me one of the zeros?
Any suggestions on how to find all the zeros?
Thank you.

1 Kommentar

Steven
Steven am 31 Mär. 2012
Here is what I have so far:
function yzero = findzeros(range)
fun=@testfun;
[yzero,value]=fzero(fun,range);
%
function fx = testfun(x)
fx=(3.*x.^3)-(12.*x.^2)-(33.*x)+80;
end
end

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Antworten (4)

bym
bym am 31 Mär. 2012

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doc roots

1 Kommentar

Steven
Steven am 31 Mär. 2012
I don't want to roots. I want to solve for all the zeros

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Wayne King
Wayne King am 31 Mär. 2012

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C = [3 -12 -33 80];
Pzeros = roots(C);
Pzeros

2 Kommentare

Steven
Steven am 31 Mär. 2012
I'm asking to find all the zeros. which are when the points cross the x-axis at x=0. You're giving me the roots.
Jared Jones
Jared Jones am 14 Mär. 2016
the roots of the function are all the points where your function equals zero. fzero is mainly used for nonlinear functions.

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Wayne King
Wayne King am 31 Mär. 2012

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Steven, In this case the roots are exactly the points you are looking for.
Please convince yourself:
C = [3 -12 -33 80];
Pzeros = roots(C);
x = -10:0.01:10;
y = 3*x.^3-12*x.^2-33*x+80;
plot(x,y)
grid on;
hold on
plot(Pzeros,zeros(length(Pzeros)),'r*','markersize',10);

3 Kommentare

Steven
Steven am 31 Mär. 2012
Ok, thats how it looks on my graph. But how would I do this in terms of using a primary function and subfunction to compute the zeros and display the answers?
Wayne King
Wayne King am 31 Mär. 2012
Write the primary function to accept the coefficients of the polynomial like the C vector above. Use roots() as a subfunction to find the zeros and then check the sign of the polynomial to the left and right of the zero, then you'll know whether it crosses the x-axis.
Steven
Steven am 31 Mär. 2012
Here is what I have so far:
function yzero = findzeros(range)
fun=@testfun;
[yzero,value]=fzero(fun,range);
%
function fx = testfun(x)
fx=(3.*x.^3)-(12.*x.^2)-(33.*x)+80;
end
end
Then I typed this into the command window:
yzero = findzeros([-10, 10])
yzero =
5.1309
All I get is 1 zero. How do I get it to display all of them?

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bym
bym am 1 Apr. 2012

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if you insist on using a subfunction , consider the following:
function x = myroots(y)
% y is an integer range to find the roots in
n = y(1):y(2);
for k = 1:numel(n)
fx=@(x)(3.*x.^3)-(12.*x.^2)-(33.*x)+80;
r(k) = fzero(fx,k);
end
separate(r)
function a = separate(r)
a = sort(r(abs(diff(r))>10*eps));
end
end
however it is sensitive to range given. Works for range[-10,10], other ranges may give different results

1 Kommentar

Walter Roberson
Walter Roberson am 1 Apr. 2012
That's an example of a function that is a nested function but not a subfunction. To be a subfunction there would have to be a shared variable.

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am 31 Mär. 2012

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am 14 Mär. 2016

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