How to replace values in a matrix according to the reference matrix

Assume matrix A and reference matrix B as follow:
A = [
1
4
8
10
3
2
7
6
3
6
];
% in matrix B two rows has 100 difference.
B = [
1 240
2 340
3 440
4 540
5 640
6 740
7 840
8 940
9 1040
10 1140
];
I want to replace matrix A's array according to the reference matrix B.
C = [
1 240
4 540
8 940
10 1140
3 440
2 340
7 840
6 740
3 440
6 740
];

1 Kommentar

Stephen23
Stephen23 am 21 Mai 2017
Bearbeitet: Stephen23 am 21 Mai 2017
@Zhan: you keep asking questions, but you have never accepted any of the answers to any of your questions. Accepting answers shows which answer solved your question, and is also an easy way for you to say "thank you" for our volunteer effort helping you.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 21 Mai 2017
Bearbeitet: Andrei Bobrov am 21 Mai 2017
just
out = B(A,:)
or general case
[~,ii] = ismember(A,B(:,1));
out = B(ii,:);

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