Filter löschen
Filter löschen

How to obtain a numeric vector with the position of elements of an array regarding another array?

1 Ansicht (letzte 30 Tage)
I have many pairs of arrays (one is the reference and other a with the same elements but with different position) and I need a numeric vector with the position of the elements in the array.
For example, this will be my references:
ref1={'a' 'b' 'c'};
ref2={'a' 'c' 'c' 'c' 'b'};
ref3={'b' 'b' 'c' 'a'};
ref4={'a' 'b' 'c' 'd'};
and this the same arrays but sorted randomly
messy1={'b' 'a' 'c'};
messy2={'c' 'c' 'c' 'b' 'a'};
messy3={'c' 'a' 'b' 'b'};
messy4={'a' 'b' 'c' 'd'};
I would like to obtain something like this:
positionVector1=[2 1 3];
positionVector2=[2 3 4 5 1];
positionVector3=[3 4 1 2];
positionVector4=[1 2 3 4];
the previous examples were just the general idea but the arrays from which I need a numeric vector are like this:
ref={'10fthf[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]' 'atp[m]'};
messy={'10fthf[m]' 'atp[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]'};
positionVector=[1 6 2 3 4 5];
Could you help me with this, thanks in advance!
note: the repeated elements are always together but I need them with a different value in the vector

Akzeptierte Antwort

Stephen23
Stephen23 am 9 Mai 2017
Bearbeitet: Stephen23 am 9 Mai 2017
Creating numbered variables is not a good code design decision, so the first thing we should do is store that data in nested cell arrays:
C = {{'a' 'b' 'c'};
{'a' 'c' 'c' 'c' 'b'};
{'b' 'b' 'c' 'a'};
{'a' 'b' 'c' 'd'}};
D = {{'b' 'a' 'c'};
{'c' 'c' 'c' 'b' 'a'};
{'c' 'a' 'b' 'b'};
{'a' 'b' 'c' 'd'}};
[~,idc] = cellfun(@sort,C,'uni',0);
[~,idd] = cellfun(@sort,D,'uni',0);
[~,idd] = cellfun(@sort,idd,'uni',0);
idx = cellfun(@(c,d)c(d),idc,idd,'uni',0);
and tested:
>> idx{1}
ans =
2 1 3
>> idx{2}
ans =
2 3 4 5 1
>> idx{3}
ans =
3 4 1 2
>> idx{4}
ans =
1 2 3 4
  2 Kommentare
Stephen23
Stephen23 am 9 Mai 2017
Bearbeitet: Stephen23 am 9 Mai 2017
@German Preciat Gonzalez: Note that my answer is much simpler than the one that you accepted:
>> ref={'10fthf[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]' 'atp[m]'};
>> messy={'10fthf[m]' 'atp[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]' 'glu_L[m]'};
>> [~,idr] = sort(ref);
>> [~,idm] = sort(messy);
>> [~,idm] = sort(idm);
>> idr(idm)
ans =
1 6 2 3 4 5
My answer is also four times faster (1000 iterations):
Elapsed time is 1.7631 seconds. % KL's code
Elapsed time is 0.448025 seconds. % my code

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

KL
KL am 9 Mai 2017
Bearbeitet: KL am 9 Mai 2017
in = cellfun(@strcmp, repmat(ref1,numel(messy1),1), repmat(messy1',1,numel(ref1)))
[I,~]=find(in'>0);
I'
for repeating elements as in ref2,you need to get rid of the repeating indices as well,
[b,m1,n1] = unique(I','first');
[c1,d1] =sort(m1);
b = b(d1)
  5 Kommentare
Stephen23
Stephen23 am 9 Mai 2017
Bearbeitet: Stephen23 am 9 Mai 2017
See my answer for a simpler solution. My answer uses fewer commands and is four times faster than KL's answer (1000 iterations):
Elapsed time is 1.7631 seconds. % KL's answer
Elapsed time is 0.448025 seconds. % my answer
KL
KL am 9 Mai 2017
Cool, I just wanted to stick to strcmp to compare ref and mess. I appreciate you took time to compare our codes

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Interactive Control and Callbacks finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by