How to replace the diagonal elements of a matrix with 0 fro avoiding self loops?
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SUNANNA S S
am 19 Apr. 2017
Kommentiert: tommsch
am 28 Jun. 2024 um 8:33
I have a matrix
M= 1 0 0 0 1 0
0 1 0 1 0 0
0 0 1 0 1 1
1 0 0 1 0 0
1 1 1 0 0 0
0 0 0 1 0 1
I want to replace all the diagonal elements in this matrix to 0 if it is 1.
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Ramtin Nazerian
am 21 Dez. 2022
Out = M.*-(eye(height(M))-1);
This will make all the diagonal values of your matrix zero as long as the matrix is square. hope that helps :).
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Stephen23
am 19 Apr. 2017
Bearbeitet: Stephen23
am 19 Apr. 2017
Method one: indexing:
M(1:1+size(M,1):end) = 0
Method two: eye:
M.*~eye(size(M))
1 Kommentar
Stephen23
am 19 Apr. 2017
A strict interpretation of the question requires only diagonals equal to one get changed to zero: this is easy to implement with eye:
M.*~(eye(size(M)) & M==1)
Roger Stafford
am 19 Apr. 2017
If your matrix M is not square and if you only want those diagonal elements changed to zero “if it is 1”, then you can do the following. Other diagonal elements not equal to one will remain unchanged. (Your description was perhaps a little ambiguous on this latter point.)
[m,n] = size(M);
d = 1:m+1:min(m^2,m*(n-1)+m);
f = find(M(d))==1;
M(d(f)) = 0;
4 Kommentare
Zeina Abdullah
am 5 Jan. 2022
@Stephen can you help me by try to answer the last question in my profile please
Christine Tobler
am 23 Mai 2017
Bearbeitet: Christine Tobler
am 23 Mai 2017
If you are using the graph/digraph classes, you can also tell the constructor not to insert any self-loops for the diagonal elements:
g = graph(A, 'omitSelfLoops');
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