Image acquisition in matlab
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
can we feed a hundred images sequentially at once in matlab with a single instruction?
0 Kommentare
Antworten (5)
Image Analyst
am 27 Mär. 2012
What do you mean by "sequentially" when you have a single instruction? I would think that a "single instruction" would mean that you process all the images "at one time" rather than "sequentially." For example
output = myFunction(image1, image2, image3, ........image100);
You're passing all 100 images to myFunction "at the same time" even though internally myFunction may be processing them sequentially.
7 Kommentare
Image Analyst
am 22 Apr. 2012
Try the montage() function or sum them and divide by 100. But I already said this above, and so did you, so we're going in circles here. You told Walter that it was too tough to do this
for k = 1:100
filename = % whatever it is.
thisImage = imread(filename);
if k == 1
sumImage = double(thisImage);
else
sumImage = sumImage+double(thisImage);
end
end
meanImage = uint8(sumImage/100);
How can we help you?
Geoff
am 27 Mär. 2012
If you're trying to emulate camera image acquisition using stored images, you could set up a timer to deliver a set of images at a set frame rate:
doc timer
4 Kommentare
Image Analyst
am 29 Mär. 2012
Huh??? Well, just throw away all images except for the final image. Or was something not explained properly?
Jakob Sørensen
am 27 Mär. 2012
Depends on how you want to combine them. If the file names are somewhat reasonable (i.e. identical like file001.jpg, file002.jpg, ...), it's rather easy to make. Then you just load one at a time into a new variable and then combine them in the end. Or you could load one, plot it, and clear the memory. Whatever suits you best. The code for loading them one at a time would be something like this:
addpath('pathname')
imageStruct = struct;
for c = 1:100
filename = sprintf('file%3.3d.jpg',c);
imageStruct.c = imread(filename);
end
1 Kommentar
Walter Roberson
am 27 Mär. 2012
http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F
Image Analyst
am 26 Apr. 2012
For your Answer to your own question,.... see the FAQ for a variety of ways to process a sequence of files. http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F
1 Kommentar
Walter Roberson
am 26 Apr. 2012
Yup. Toss them all into a cell array "z", then
t1 = num2mat(ones(numel(z),1));
t2 = [t1, z(:)];
z100 = imlincomb( t2{:}, 'uint8');
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!