Print a table with 4 columns fprintf

   95.0000    1.8700   10.9831    8.9874
    2.0000   45.0000    1.6000    7.1402
    3.0000   76.0000    1.7000    9.3224
    4.0000   88.0000    1.6100    9.5381
    5.0000   55.0000    1.5000    7.4204
    6.0000   50.0000    1.6100    7.5010
    7.0000   61.0000    1.5800    8.0519
    8.0000  105.0000    1.8300   11.2821

I specify the vectors like this: N=[1,2,3,4,5,6,7,8]; and I use fprintf(fileID,'%5.2f\n\' but if i repeat this for my other variable it all ends up in one column?How to get it in 4 columns

Answer 1

[KSSV]

A = magic(5) ;
 fprintf([repmat('%f\t', 1, size(A, 2)) '\n'], A')

[Stephen23]

Note that transpose A.' should be used, and not conjugate transpose A'.

Answer 2

[Stephen23]

When you put all of the data into one matrix then your task is easy:

>> M = [95,   1, 10.9831,  8.9874;...
         2,  45,  1.6000,  7.1402;...
         3,  76,  1.7000,  9.3224;...
         4,  88,  1.6100,  9.5381;...
         5,  55,  1.5000,  7.4204;...
         6,  50,  1.6100,  7.5010;...
         7,  61,  1.5800,  8.0519;...
         8, 105,  1.8300, 11.2821];
>> fmt = '%3d,%4d,%6.2f,%6.2f\n';
>> fprintf(fmt,M.')
 95,   1, 10.98,  8.99
  2,  45,  1.60,  7.14
  3,  76,  1.70,  9.32
  4,  88,  1.61,  9.54
  5,  55,  1.50,  7.42
  6,  50,  1.61,  7.50
  7,  61,  1.58,  8.05
  8, 105,  1.83, 11.28

Note that I specified different formats for each column, and used transpose M.' instead of the linear algebra operation ctranspose M'.