I want to be able to detect when a sequence of numbers starts and finishes in an array. For example, if I have
A = [1 0 1 0 1 0 1 1 0 0 1 1 0 0 1 1 0 0 1 0 1 0 1 0];
B = [1 1 0 0];
Can I determine whether A contains B and if A does contain B, get the index of A that B starts and stops (so 7 and 18 here)
Thank you

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the cyclist
the cyclist am 17 Mär. 2017
Bearbeitet: the cyclist am 17 Mär. 2017

7 Stimmen

Even though these are not strings, you can use strfind as the key component to doing what you want
strfind(A,B)
will find the starting indices where B is embedded in A.
It is not perfectly clear to me how you want to handle repetitions, or repetitions with gaps, etc. So, maybe this is enough to get you started?

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Jan
Jan am 17 Mär. 2017

3 Stimmen

The sequence is found at the positions 7, 11 and 15. If you search for "7, 18", I guees you want:
Index = strfind(A, B);
Result = [Index(1), Index(end) + length(b) - 1];
A fallback is required, when no match is found.

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am 17 Mär. 2017

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Jan
am 17 Mär. 2017

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