how to sort the vectors to positive n negative of same elements?

Hi All, say i have a vector v = [1,-2,3,4,5,6,7,8,9,77,44,88,99,-1,95,-6,-7,-8,-9] now i want to check element by element if there is a same element with opposite sign(1, -1) in the array and plot it as zero in their respective points in the x axis. Please note: i do not need to store the values in the variable and just need to plot it. How can i implement that?

thanks

Answer 1

[Stephen23]

>>  v = [1,-2,3,4,5,6,7,8,9,77,44,88,99,-1,95,-6,-7,-8,-9]
v =
    1   -2    3    4    5    6    7    8    9   77   44   88   99   -1   95   -6   -7   -8   -9
>> out = v .* ~ismember(v,-v)
out =
    0   -2    3    4    5    0    0    0    0   77   44   88   99    0   95    0    0    0    0
>> plot(out)

[Jayanta Deb]

Hi Stephen, thanks for your help, but i need to plot only those numbers which are same(both positive and negative) as a positive point in x axis. like the points which got zero i need them to be plotted as a positive number on the x axis. Just the opposite of what the output you gave thanks

[Stephen23]

Then do the opposite:

 out = v .* ismember(v,-v)

If neither of these resolve your question then please explain exactly what you want together with example input and output data. Your original question states "..if there is a same element with opposite sign(1, -1) in the array and plot it as zero..", and that is exactly what my answer gives you: values which are both positive and negative in the vector are plotted as zero.

[Jayanta Deb]

thanks Stephen