How to compare matrix of different dimensions?

I've read the other posts regarding this problem and I'm kinda confused on how to compare 2 matrices of different dimensions. Say I have this code where the array ww is a 43x1 and the array w3 ended up being 20x1

ww=mean(array1,2)
w1=mean(array2,2)
w2=mean(array2,2)>5
w3=w1(w2)
w5=ww<w3

How can get the statement w5=ww<w3 to work (ie. compare those arrays)?

[KSSV]

You cannot compare two different sized matrices. What is the purpose to compare?

[Chibuzo Nnonyelu]

Since the matrices are of different dimensions, a one-to-one comparison is mathematically and programmatically invalid. However, if you want a one-to-all comparison, then if it better to use a loop.

[Beder]

I assume you want to have w3 containing the elements where the mean of array2 is >5. To achieve this you can use logical indexing:

w2(w1>5)=w1;
w5=ww<w2

is that what you wanted?

[Jan]

If the array has the size [43 x 1], the command mean(array, 2) does not do anything. Please give a small example with example data to explain, what you want to calculate. Seeing not working code is not enough to reconsider your intention.