random no.

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huda nawaf
huda nawaf am 18 Mär. 2012
hi, can i get random no. in specific range ?
between 19 , -19
thanks
  1 Kommentar
Oleg Komarov
Oleg Komarov am 18 Mär. 2012
Yes, you can.

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Antworten (4)

Image Analyst
Image Analyst am 18 Mär. 2012
You didn't read the help on rand(), did you? If you had, you would have seen the answer to your question as the very first example:
Example 1
Generate values from the uniform distribution on the interval [a, b]:
r = a + (b-a).*rand(100,1);
Needless to say, a=-19 and b = 19 in your case, and 100 is the number of random numbers to be generated, or:
r = -19 + 38 .* rand(100, 1);
  1 Kommentar
Jan
Jan am 18 Mär. 2012
While the solution in easy, not to say trivial, the suggestion to read the documentation is an will be valuable. +1

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the cyclist
the cyclist am 18 Mär. 2012
Depending on whether you want to draw from a discrete or a continuous distribution, you will likely want to use either the randi() or unifrnd() function.

Sean Lawson
Sean Lawson am 18 Mär. 2012
naively, this works: 38*(rand-0.5)

Sahyadri Vibhu
Sahyadri Vibhu am 20 Mär. 2012
As Sean Lawson said in the above comment, using -19+38*rand will generate a random real number in the range (-19 19)
to generate random integers use
randi ([lower_limit upper_limit],a,b,c...)
which generates an axbxcx..... random integer array in the range (lower_limit upper_limit)

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