if true
clc;clear;close;
format long
syms x
f=0.0000095862*((x+1.4051)^0.44267)*((6.4051-x)^5.5867);
g=diff(f,x);
g2=diff(f,2);
h=solve(g==0)
h2=solve(g2==0)
A=subs(f,x,h)
end
A must be double? Why it is sym in workplace ? Besides I have some warnings; Warning: Cannot solve symbolically. Returning a numeric approximation instead.

 Akzeptierte Antwort

John D'Errico
John D'Errico am 16 Feb. 2017
Bearbeitet: John D'Errico am 16 Feb. 2017

0 Stimmen

Why MUST A be a double? Did you not create it as symbolic? Even though the result is a "number", it can still be stored as a symbolic form, so many digits. It will be, since how does MATLAB know that at the end, you want it as a double? How does MATLAB know that you will not now do something else with A that requires symbolic computation?
For example, you compute both h and h2 along the way. Both of them are only precursors to the final value of A, yet both of them were in symbolic form too. Would you have wanted MATLAB to arbitrarily decide that h and h2 are numbers,so it should convert them in to doubles,losing all of those extra digits along the way? While it might not matter here, it surely will matter some other time.
However, nothing stops you from now converting A INTO a double, as long as it is purely numeric. Try these things:
help sym/double
A = double(A);

1 Kommentar

Hatem Çoban
Hatem Çoban am 17 Feb. 2017
I got it. thanks a lot for answer. Fisrtly I didn't notice but I understood my mistake after I sent this question.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by