I can use the datenum command for individual cells, but can not seem to apply it to a whole column. What am I doing wrong? Thanks, Stephen

 Akzeptierte Antwort

Honglei Chen
Honglei Chen am 15 Mär. 2012

0 Stimmen

try cellfun
cellfun(@datenum,...
see the doc
doc cellfun

Weitere Antworten (1)

Jan
Jan am 15 Mär. 2012

0 Stimmen

datenum does accept a column cell:
datenum({'15-Mar-2012 23:53:23'; '15-Mar-2012 23:53:23'})
>> ans =
7.3494e+005
7.3494e+005

3 Kommentare

Stephen Jones
Stephen Jones am 16 Mär. 2012
Jan,
Thanks, but I have a long column of dates, in the format of yyyymmdd. Is there a way to use datenum in this situation?
Stephen
Jan
Jan am 16 Mär. 2012
I suggest to read the documentation: help datenum, doc datenum
There you find:
datenum({'20120315'; '20120316'}, 'yyyymmdd')
Sara Mendiola
Sara Mendiola am 1 Mär. 2017
How about datestr for a column?

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