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Array function for ranges

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Azura Hashim
Azura Hashim am 7 Feb. 2017
Bearbeitet: Jan am 15 Feb. 2017
Hi,
I have a binary image in a matrix, call it binarymage. I then want to determine whether various areas in the image are white pixels only. The boundaries for the areas of interest are defined in as follows:
left=[1]; right=[11]; top=[5,6,7,8]; bottom=[15,16,17,18];
So in this example I have 4 boxes. How can get a result that tells me which boxes are white only. Example: whiteboxes=[1,0,1,0].
I think I need arrayfun but have not been successful after several attempts. Appreciate any help please. Thank you.

Akzeptierte Antwort

Saurabh Gupta
Saurabh Gupta am 15 Feb. 2017
You should be able to do it using a combination of not and any commands. One example could be as follows.
tempBox = binarymage(top(1):bottom(1), left(1):right(1));
whiteboxes(1) = not(any(tempBox(:)));

Weitere Antworten (1)

Jan
Jan am 15 Feb. 2017
Bearbeitet: Jan am 15 Feb. 2017
A simple loop is a good point to start from:
left = 1;
right = 11;
top = [5,6,7,8];
bottom = [15,16,17,18];
whiteboxes = false(1, 4);
for k = 1:4
whiteboxes(k) = all(binarymage(left:right, top(k):bottom(k)));
end
What exactly is a "white" pixel? Does it have the value 1 or 0? Here I assume, that white mean 1. If 0 is meant, replace all() by ~any().

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