How can I use a string input in a "for" loop to get a matrix of names?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
for i=0:2
a(i)=input('enter your name?','s')
end
what's wrong with this code? Matlab cannot read names I give to it. and here is the error: "Subscript indices must either be real positive integers or logicals."
2 Kommentare
Stephen23
am 1 Feb. 2017
Note: the original question used an if:
if i=0:2
a(i)=input('enter your name?','s')
end
Antworten (2)
Alexandra Harkai
am 1 Feb. 2017
The problem with this code is that (in MATLAB) indexing is from 1, not 0. Therefore a(0) is giving you the error.
As for the for loop (not if), if you want 3 inputs:
for i=1:3
a(i)=input('enter your name?','s');
end
1 Kommentar
Star Strider
am 1 Feb. 2017
That’s not the only problem. For any name longer than one letter, it will throw a
Subscripted assignment dimension mismatch.
error.
You have to use a cell array (notice the curly brackets ‘{}’ designating it as a cell array):
for i=1:3
a{i}=input('enter your name?','s');
end
Note: In all answers and comments, please test your code before posting it if at all possible. If you cannot, always label it as ‘untested code’.
Stephen23
am 1 Feb. 2017
Bearbeitet: Stephen23
am 1 Feb. 2017
Your code has multiple mistakes: MATLAB indexing starts from one, you need to use a for loops, and you need to use a cell array:
N = 3;
C = cell(1,N);
for k = 1:N
C{k} = input('enter your name: ','s');
end
You should do the introductory tutorials, because they teach these very basic MATLAB concepts:
And also read this:
0 Kommentare
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!