points lying inside a polygon and a circle

How can I find the number of point lies inside both a circle and a polygon (the point should lie in the mutual/overlapping area in between the circle and the polygon) ?

 Akzeptierte Antwort

Matt J
Matt J am 30 Jan. 2017
Bearbeitet: Matt J am 25 Apr. 2019

0 Stimmen

If the circle is centered at (x0,y0), with radius R and the polygon has vertices xv,yv, you could do,
count = sum( inpolygon(x,y,xv,yv) & ((x-x0).^2+(y-y0).^2<=R^2) )

3 Kommentare

KalMandy
KalMandy am 30 Jan. 2017
what is the output of (x-x0).^2+(y-y0).^2<=R^2) ? does it become 1, if the point is inside the circle?
Matt J
Matt J am 30 Jan. 2017
Yes.
KalMandy
KalMandy am 30 Jan. 2017
Thanks a lot!

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Weitere Antworten (1)

Image Analyst
Image Analyst am 30 Jan. 2017

2 Stimmen

Did you try
count = 0;
if inpolygon(x,y,xCircle,yCircle) && inpolygon(x,y,xPoly,yPoly)
count = count + 1
end
where you call inpolygon twice, once passing in the circle coordinates and once passing in the polygon coordinates and then ANDing the two results together?

6 Kommentare

KalMandy
KalMandy am 30 Jan. 2017
can I use inpolygon for a circle as well?
Image Analyst
Image Analyst am 30 Jan. 2017
Bearbeitet: Image Analyst am 30 Jan. 2017
Yes, if you have the coordinates for the perimeter of the circle. If you don't, then see Matt J's formula below. You didn't specify in what form you have information about the circle. You'd put my code in a loop over all (x,y) points that you have.
count = 0;
for k = 1 : length(x)
if inpolygon(x(k),y(k),xCircle,yCircle) && inpolygon(x(k),y(k),xPoly,yPoly)
count = count + 1
end
end
Same for Matt's code - loop over all x,y that you have.
Matt J
Matt J am 30 Jan. 2017
Same for Matt's code - loop over all x,y that you have.
Neither approach requires a loop over x,y. INPOLYGON is vectorized.
You're right. x and y can be a vector of coordinates. Here's a demo:
% Make circle.
x0 = 20;
y0 = 30;
R = 15;
% Plot circle
pos = [x0-R, y0-R, 2*R, 2*R];
rectangle('Position', pos, 'Curvature',[1 1]);
hold on;
% Make polygon
xv = [10, 30, 30, 10, 10];
yv = [40, 40, 5, 5, 40];
plot(xv, yv, 'b-');
grid on;
% Make 60 points for x and y
numPoints = 60;
x = 70 * rand(1, numPoints);
y = 70 * rand(1, numPoints);
plot(x, y, 'r*');
% Now count how many are in both the circle and the polygon.
count = sum(inpolygon(x,y,xv,yv) & ((x-x0).^2+(y-y0).^2<=R^2))
KalMandy
KalMandy am 30 Jan. 2017
I have the radius and the coordinates of the center of the circle. what is given by xCircle,yCircle? Thanks for your response.
hanif hamden
hanif hamden am 25 Apr. 2019
If i put (x,y) in geographical coordinate and I want my radius is 10km. How should I do that?

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