LU decomposition

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Zdenek
Zdenek am 11 Mär. 2012
Hi, i´m a begginer(looser) in matlab and i don´t know, where is problem in this script. Please help me and thanks for tips.
function [L, U, P] = LURozklad(A)
P = eye(size(A));
L = P;
A_pred = A;
P_pred = P;
for k = 1:size(A) - 1
r = IPR(A, k, k);
A_pred = A;
A = VymenaRadkuMatice(A, k, r);
P_pred = VymenaRadkuMatice(P_pred, k, r);
P = P_predchozi;
for i = k + 1:size(A)
m_ik = A(i, k)/A(k, k);
for j = k + 1:size(A)
A(i, j) = A(i, j) - m_ik * A(k, j);
end
A(i, k) = m_ik;
end
printf('matice A: ', A);
for i = 2:size(A)
for j = 1:size(A)
if i > j
L(i, j) = A(i, j);
end
end
end
printf('matice L: ', L);
for i = 1:size(A)
for j = 1:size(A)
if i <= j
U(i, j) = A(i, j);
end
end
end
printf('matice U: ', U);
P = P_predchozi;
printf('matice P:', P);
end
function [r] = IndexPivotnihoRadku(A, OdRadku, IndexSloupce)
MaxHodnota = 0;
for i = OdRadku:size(A)
if abs(A(i,IndexSloupce)) > MaxHodnota
MaxHodnota = abs(A(i,IndexSloupce));
r = i;
end
end
function [A] = VymenaRadkuMatice(A, radek1, radek2)
PomocnyRadek = A(radek1,:);
A(radek1, :) = A(radek2,:);
A(radek2, :) = PomocnyRadek;
end
function printf(string, value)
disp(string);
disp(value);
end
end
end
  1 Kommentar
Jan
Jan am 12 Mär. 2012
Please explain, why you are thinking, that this function has a problem.

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