6*3 matrix and put each value row wise in equation f(x,y,z)= [(X-0.33).​^2+(Y-0.33​).^2+(Z-0.​33).^2] and calculate the answer and store that value as 4th column in matrix

firstpop =

     x     y     z  f(x,y,z)
     6     1     2  
     2     5     2   
     7     1     1
     2     6     1
     1     2     6
     0     0     9

Answer 1

[KSSV]

What is there to do in your question? It is very easy and straight forward. I advice you to read MATLAB basics, it is very straight forward job.

1. Let data be your 6X3 matrix.
2. Take x,Y and Z from the data. X = data(:,1) ; Y = data(:,2) ; Z = data(:,3) ;
3. Define your formula: f= (X-0.33).^2+(Y-0.33).^2+(Z-0.33).^2 ;
4. You got f, append it to the data.

Answer 2

[Image Analyst]

If a 3D array is wanted for f instead of a 1-D vector (it's hard to tell from your description), then you need to use meshgrid().

%   x     y     z  f(x,y,z)
firstpop =[...
  6     1     2
  2     5     2
  7     1     1
  2     6     1
  1     2     6
  0     0     9]
x = firstpop(:, 1);
y = firstpop(:, 2);
z = firstpop(:, 3);
% Get all possible combinations
[X, Y, Z] = meshgrid(x, y, z);
% Now compute the 3-D matrix:
f = (X-0.33).^2+(Y-0.33).^2+(Z-0.33).^2;

Now f is a 3D array instead of a 1-D array like in KSSV's solution.