Printing cell arrays issue

So, I have two cell arrays. For illustration purpose, let's call them A and B. Cell A and B are both 1x6 cells, let's say that the first elements of A are 1 and 2 and the first element of B is 7. I want to print them so that the value of B stays in the middle of the elements of A, i.e, -> 1 [7] 2. Problem is, when I try to print it, it prints all of the values inside of the cell A and only then the value of B, like 1 [2] 7.

Any ideas?

[David Barry]

Are there always two elements in each cell of A and one in each cell of B? If not, what should happen?

[Nuno Palma]

This is part of a more complex problem involving the Dijkstra function. One of the cells contain the paths and the other the distances between them.

I'm already in the end of the project and I'm having issue just showing the results xD

Basically, the cell 'B' will always have one less element than the other one. I just can't seem to print them out in the order I wish, which would be printing one element of A, than one of B, and so on

[Nuno Palma]

for i = 1:amountofpaths
  if dist(i) ~= 0
      for j = 1:length(path{i})
          fprintf('%d ',path{i}(j));
      end
      for k = 1:length(dist_parc{i})
          fprintf(' (%d) ', dist_parc{i}(k));
      end
      fprintf('| Total = %d', dist(i));
      fprintf('\n');

    end
  end
end

This is the loop I'm using, and this is the result:

1 2  (7) | Total = 7
1 3  (9) | Total = 9
1 3 4  (9)  (11) | Total = 20
1 3 6 5  (9)  (2)  (9) | Total = 20
1 3 6  (9)  (2) | Total = 11

The values in parentheses should be between the other ones. Any ideas?

Answer 1

[Stephen23]

Do not use path as a variable name. As you have already been told, this is the name of a very important inbuilt function path. Use which to check if a name is already in use.

Try this code:

A = {[1,2],[1,3],[1,3,4],[1,3,6,5],[1,3,6]};
B = {  7,    9,   [9,11], [9,2,9],  [9,2]};
C = {7,9,20,20,11};

for k = 1:numel(C)
    tmp = [[NaN,B{k}];A{k}];
    fprintf('%d ',tmp(2));
    fprintf('(%d) %d ',tmp(3:end))
    fprintf('| Total = %d\n', C{k})
end

Which prints this:

1 (7) 2 | Total = 7
1 (9) 3 | Total = 9
1 (9) 3 (11) 4 | Total = 20
1 (9) 3 (2) 6 (9) 5 | Total = 20
1 (9) 3 (2) 6 | Total = 11

[Nuno Palma]

Yes, I forgot to change the variable's name. Wasn't aware it was already built-in matlab.

About the code, I had tried to concatonate them before and I got the same error with this code. 'Error using vertcat Dimensions of matrices being concatenated are not consistent.

I searched it up and it seems all the matrices being concatonated need to have the same number of columns.

I figured out that my 'B' variable has one more element, which is zero, and doesn't even go up for calculations, I think it'd work if I removed it

[Nuno Palma]

Done. Thanks a lot! :) And for the path input as well !