end
States
Basically it outputs an array of size (N,1) consisting of 1s and -1s.
How can I repeat this array for example 5 times using the updated values of 'States', whilst displaying the results of each loop?

1 Kommentar

James Tursa
James Tursa am 30 Nov. 2016
"... using the updated values of 'States' ..."
What does this mean? I don't see 'States' used anywhere in the loop. Certainly you could wrap your current loop inside another loop, but how is 'States' supposed to be used in this loop?

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

James Tursa
James Tursa am 30 Nov. 2016

0 Stimmen

Is this all you are trying to do?
n = number of times to repeat the loop
States = zeros(size(N,1));
for k=1:n
for ii = 1:numel(AgentZScore)
% etc
end
States
end

1 Kommentar

dpb
dpb am 30 Nov. 2016
NB: The existing loop can be replaced w/ a one-liner, though...

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (2)

Jan
Jan am 30 Nov. 2016
Bearbeitet: Jan am 30 Nov. 2016

1 Stimme

Simply include in a for loop:
n = 5;
for k = 1:n
.... your code
end
dpb
dpb am 30 Nov. 2016
Bearbeitet: dpb am 1 Dez. 2016

0 Stimmen

Above loop can be simply
states=2*(cdf('norm',z,0,1)>rand(size(z)))-1;
where z <--> AgentZScore
To repeat, simply incorporate in a loop save each trial as a new column in 2D array would be simplest.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Produkte

Gefragt:

am 30 Nov. 2016

Kommentiert:

am 29 Sep. 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by