Koch Square Problem : A(I): index out of bounds; value 4 out of bound 3

Can someone please fix my error?

Answer 1

[Walter Roberson]

You use newpointsx(4) and newpointsy(4) before you have assigned anything to those locations. Two lines further on you use the (5) indices too.

[Mohanad Arafae]

I don't quite understand what you are saying, what do you suggest me to do?

[Mohanad Arafae]

It's giving me anther error now

[Jan]

@Mohanad Arafae: All information we have is the failing code. We cannot guess magically its intention. Therefore it is hard to suggest an improvement.

[Walter Roberson]

Your code has

v=[newpointsx(4);newpointsy(4)]-[newpointsx(2);newpointsy(2)]
vprime = R*v
f=[newpointsx(5);newpointsy(5)]-[newpointsx(3);newpointsy(3)]
fprime = R*f

newpointsx(4) = vprime(1)+newpointsx(2) %Point D
newpointsy(4) = vprime(2)+newpointsy(2)

newpointsx(5) = fprime(1)+newpointsx(3) %Point F
newpointsy(5) = fprime(2)+newpointsy(3)

Notice that you use newpointsx(4) and newpointsy(4) in calculating v, but you do not assign any value to newpointsx(4) or newpointsy(4) until 5 lines later in the code.

You need to assign values to newpointsx(4), newpointsx(5), newpointsy(4), newpointsy(5) before you can use them in calculations.

[KSSV]

@ Walter Roberson, I apologize, I have not seen all this discussion and in hurry closed the question. I shall be careful next time.