can anyone tell me how to implement DTMF tone using matlab and i have to listen the tone

2 Kommentare

Deema Hani
Deema Hani am 4 Jan. 2022
xK(t)=sin(2*3.4ft)+sin(2*3.4gt),
0<=t<=Td
1) Develop a function namde ss_(..)to produce the signal for one digit.The synatax of the function should be
x=ss_dtmf(n,t)

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pavan chillapur
pavan chillapur am 3 Okt. 2016
Bearbeitet: Stephen23 am 3 Okt. 2016

4 Stimmen

symbol = {'1','2','3','4','5','6','7','8','9','*','0','#'};
lfg = [697 770 852 941]; % Low frequency group
hfg = [1209 1336 1477]; % High frequency group
f = [];
for c=1:4,
for r=1:3,
f = [ f [lfg(c);hfg(r)] ];
end
end
Fs = 8000; % Sampling frequency 8 kHz
N = 800; % Tones of 100 ms
t = (0:N-1)/Fs; % 800 samples at Fs
pit = 2*pi*t;
tones = zeros(N,size(f,2));
for toneChoice=1:12,
% Generate tone
tones(:,toneChoice) = sum(sin(f(:,toneChoice)*pit))';
% Plot tone
subplot(4,3,toneChoice),plot(t*1e3,tones(:,toneChoice));
title(['Symbol "', symbol{toneChoice},'": [',num2str(f(1,toneChoice)),',',num2str(f(2,toneChoice)),']'])
set(gca, 'Xlim', [0 25]);
ylabel('Amplitude');
if toneChoice>9, xlabel('Time (ms)'); end
end
set(gcf, 'Color', [1 1 1], 'Position', [1 1 1280 1024])
annotation(gcf,'textbox', 'Position',[0.38 0.96 0.45 0.026],...
'EdgeColor',[1 1 1],...
'String', '\bf Time response of each tone of the telephone pad', ...
'FitBoxToText','on');

7 Kommentare

mohit saxena
mohit saxena am 30 Aug. 2018
on executing this program we are able to get the plot of time response of each tone of telephone pad but unable to get listen the tone. Furthermore how can I verify the obtained waveforms?
Divyanshu Singh
Divyanshu Singh am 15 Okt. 2019
Bearbeitet: Divyanshu Singh am 15 Okt. 2019
The coding provided by Pavan has many errors in it... I'll send the correct code...
Divyanshu Singh
Divyanshu Singh am 15 Okt. 2019
Bearbeitet: Divyanshu Singh am 15 Okt. 2019
if true
% code
end
symbol = {'1','2','3','4','5','6','7','8','9','*','0','#'};
lfg = [697, 770, 852, 941];
hfg = [1209, 1336, 1477];
f = [];
for c = 1:4
for r = 1:3
f = [f [lfg(c); hfg(r)]];
end
end
Fs = 8000;
N = 800;
t = (0:N-1)/Fs;
pit = 2*pi*t;
tones = zeros(N, size(f,2));
for toneChoice = 1:12
tones(:,toneChoice) = sum(sin(f(:,toneChoice)*pit));
subplot(4,3,toneChoice);
plot(t*1e3,tones(:,toneChoice));
title(['Symbol " ', symbol{toneChoice}, ' "']);
[num2str(f(1,toneChoice))];
[num2str(f(2,toneChoice))];
set(gca, 'Xlim', [0, 25]);
ylabel('Amplitude');
if toneChoice>9
xlabel('Time (ms)');
end
end
set(gcf, 'Color', [1, 1, 1], 'Position', [1, 1,1280, 1024]);
annotation(gcf, 'textbox', 'Position', [0.38, 0.96, 0.45, 0.026], 'EdgeColor', [1, 1, 1], 'String', '\bf Time response of each tone of the telephone pad', 'FitboxToText', 'on');
VIJAY CHANDRA
VIJAY CHANDRA am 17 Nov. 2020
how to execute the code in matlab
Muhammet Furkan Nargül
Muhammet Furkan Nargül am 19 Nov. 2020
Thank you!
EHTEZAZ ALI HASSAN
EHTEZAZ ALI HASSAN am 23 Jan. 2021
no sound man
ammar ansari
ammar ansari am 19 Jun. 2021
For sound you can use the code
keypad = tones(:,5),Fs,16; % 5 is button pressed on keypad
sound(keypad)
If multiple button on keypad are pressed like (5086477000) then
for i = [5 11 8 6 4 7 7 11 11 11]
p = audioplayer(tones(:,i),Fs,16);
play(p)
pause(0.5)
end

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