How can I have n randomly generated vectors?

Hi, I want to generate n random vectors. The problem is I put it in the loop and the vector is being replaced in every run, but I need to have all of the n vectors.

for n= 1:50
A=rand(1,5);
end

How can I have n random vectors as an output?

Answer 1

[Walter Roberson]

for n= 1:50
  A(n,:)=rand(1,5);
end

or

for n= 1:50
  A{i}=rand(1,5);
end

[Sherwin]

Thank you.

[Sherwin]

By the way is there any way that I get all of them in a row?

Answer 2

[Image Analyst]

Store the vectors in rows of A

A = rand(50, 5);

Anytime you need one of the vectors, just reference a row of A

thisVector = A(row, :);

[Sherwin]

It doesn't work that way. I have some row vectors generated, I want to put them one after another so that I have a long row vector.

[Image Analyst]

How were they generated? Why can't you simply do

longRowVector = [v1, v2, v3, v4, v5, v6];  % and so on.

Or

A = rand(1, 50*5);

or (least preferred of all)

longRowVector = []; % Initialize.
for n = 1 : 50
    thisA = rand(1,5);
    longRowVector  = [longRowVector, thisA];
end

[Sherwin]

Thank you!! I want to use the first option since it's simple but here I have:

for j = 1:ncolumns
          minichrom(j,:) = round(rand(1,spot_length));

And I want to have a long row vector of minichrom. Would you please help me?

[Image Analyst]

Try one of these options:

m = magic(3)
% Get m going down columns
mRow = m(:)'
% Get m going across rows
temp = m';
mRow = temp(:)'

m =
     8     1     6
     3     5     7
     4     9     2
mRow =
     8     3     4     1     5     9     6     7     2
mRow =
     8     1     6     3     5     7     4     9     2

[Sherwin]

Thank you so much!