Using for loop to evaluate polynomial for different values

 % Here N = 10 ; poly =[5 8 0]
for i = 1:N-1;
    A = sum(poly);
    B = mod(A,N); 
end
i = i + 1;

But the end result shows the value for i = 1 (i.e. A=13, B = 3) only. I need to display A & B for i = 1 to 9

Answer 1

[Image Analyst]

Try this:

N = 10 ; 
poly =[5 8 0];
for k = 1:N-1;
    A = sum(poly);
    B = mod(A,N); 
  fprintf('At iteration %d, A = %d, and B = %d\n', k, A, B);
end

You'll see

At iteration 1, A = 13, and B = 3
At iteration 2, A = 13, and B = 3
At iteration 3, A = 13, and B = 3
At iteration 4, A = 13, and B = 3
At iteration 5, A = 13, and B = 3
At iteration 6, A = 13, and B = 3
At iteration 7, A = 13, and B = 3
At iteration 8, A = 13, and B = 3
At iteration 9, A = 13, and B = 3

It displays A and B at every one of the 9 iterations, and you can see that they're all the same since A and B never are assigned anything that depends on the iteration number at all.

[Neha W]

Sir, since i = 1: 10

if want A = [0 13 36...477] (% evaluate poly for every iteration till N-1) and the store the mod values in B = [0 3...7] array, What could be the procedure?

[Image Analyst]

You need to index A and B, like A(k) and B(k). Of course since you defined poly as a constant, A and B still won't change.