So, I have created a matrix called cent in another for loop, and then:
for
... creates "cent"
end
e = 5 ;
per = zeros(e,e)
for u = 1:e
rsum = 0;
a = 0;
for p=1:e
u
p
Xdiff = 0;
Ydiff = 0;
Zdiff = 0;
Xdiff = (cent(u,1)-cent(:,1)).^2
Ydiff = (cent(u,2)-cent(:,2)).^2
Zdiff = (cent(u,3)-cent(:,3)).^2
a = (Xdiff + Ydiff + Zdiff).^0.5
rsum = cent(u,6) + cent(:,6) ;
if a == rsum(p)
per(p,u) = p ;
else
per(p,u) = 0 ;
end
end
end
The script runs just fine, and I get no error messages. However, i get no display of u and p, and per is returned as a matrix with only zeros if i create it before the first for loop. If i create per as shown below, between the two loops, it is not created at all. I thus think that the code never enters the second loop and run it. Why?

Antworten (1)

Thorsten
Thorsten am 17 Aug. 2016

0 Stimmen

I have created some sample values for cent and the program runs just fine, entering the second loop as expected. The reason that per is all zero is that the condition
a == rsum(p)
is never true.

4 Kommentare

Jonathan Oekland Torstensen
Jonathan Oekland Torstensen am 17 Aug. 2016
Are you sure? Because it never displays p or u in the promt, which it should if it runs the loop.
Jonathan Oekland Torstensen
Jonathan Oekland Torstensen am 17 Aug. 2016
Im pretty sur it doesnt run, because I get that per is undefined after running the code.
Jonathan Oekland Torstensen
Jonathan Oekland Torstensen am 17 Aug. 2016
Any other suggestions?
Image Analyst
Image Analyst am 17 Aug. 2016
Use the debugger to step through the code line by line and examine variables and see where it goes. That's what everyone does.

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