- a string
- another numeric class
- something else... ?
How do i convert scientific notation into number in matlab
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a=9.22222e+15
I need to convert this number and want to save the answer in variable
1 Kommentar
Antworten (3)
Stephen23
am 10 Aug. 2016
Bearbeitet: Stephen23
am 10 Aug. 2016
The variable a is already a numeric:
>> a = 9.22222e+15
a = 9.2222e+015
>> isnumeric(a) %check that it is a numeric
ans = 1
>> fprintf('%.0f\n',a)
9222220000000000
Why do you think that it is not a numeric ? You might like to read about the different format options, which control how numeric values are displayed in MATLAB:
Remember that how a numeric value is displayed is a totally different matter to how it is stored. For example, here are three different ways of displaying your numeric value:
>> format bank
>> a = 9.22222e+15
a = 9222220000000000.00
>> format hex
>> a = 9.22222e+15
a = 434061c7b591fc00
>> format longg
>> a = 9.22222e+15
a = 9.22222e+015
7 Kommentare
Walter Roberson
am 13 Sep. 2017
Stephen23
am 13 Sep. 2017
Bearbeitet: Stephen23
am 13 Sep. 2017
"MATLAB understand a value such as 1.0400e+4 as the whole number 10400 that it is, instead of as a non-whole number."
It certainly looks like a whole number:
>> sprintf('%.30f',1.0400e+4)
ans =
10400.000000000000000000000000000000
>> rem(1.0400e+4,1)==0
ans =
1
How would you expect it to be different from this?
"I believe what Jasmeet was asking is..."
Jasmeet did not mention "integer" or "whole" anywhere, and gave an example value that is slightly higher than flintmax, making the output value rather meaningless in terms of "whole number or not". If that is what Jasmeet and yourself are asking about then the solution is to learn about the properties of floating point numbers
Anish Vaidya
am 26 Nov. 2017
Bearbeitet: Anish Vaidya
am 26 Nov. 2017
Even, I've the same problem. I want to store a number in a variable in decimal notation and then convert to array of characters.
1 Kommentar
Walter Roberson
am 26 Nov. 2017
What form is the value in at present?
When you convert it to character, how many decimal places of precision do you need?
What is the range of values possible?
Surama Biswas
am 11 Sep. 2020
Following example by Stephen Cobeldick works for me. I need to place each bit by last fprintf in an array. Please help me. Thanks in advance.
>> a = 9.22222e+15
a = 9.2222e+015
>> isnumeric(a) %check that it is a numeric
ans = 1
>> fprintf('%.0f\n',a)
9222220000000000
2 Kommentare
Walter Roberson
am 11 Sep. 2020
Note that the result would be a character vector.
If the task is to store numeric 9222220000000000 as a double precision variable, then a = 9.22222e+15 already does that. The way that a variable displays is not the same thing as the value stored in the variable.
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