How can I find the sum of the perimeter of a matrix?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Alexandra Huff
am 5 Aug. 2016
Beantwortet: Ibrahim Abouemira
am 19 Mai 2019
Hi, I am wondering if I had a matrix [1,2,3;1,2,3;1,2,3] how I could find the sum of the perimeter. Thanks an advance.
0 Kommentare
Akzeptierte Antwort
dpb
am 5 Aug. 2016
One way amongst any number...
>> M=[1,2,3;1,2,3;1,2,3];
>> I=ones(size(M)); I(2:end-1,2:end-1)=0;
>> S=sum(reshape(M.*I,1,[]))
S =
16
>>
0 Kommentare
Weitere Antworten (3)
Stephen23
am 5 Aug. 2016
Bearbeitet: Stephen23
am 5 Aug. 2016
In one line is easy and very fast:
>> M = [1,2,3;1,2,3;1,2,3];
>> sum(sum([M([1,end],2:end-1),M(1:end,[1,end]).']))
ans = 16
5 Kommentare
dpb
am 10 Feb. 2018
[ ... Ricardo Florez Answer moved to comment since was a follow-up question on earlier Answer syntax ... dpb]
Hi. Why is it necessary to write two "sum" in the code: sum(sum(M(...)? Please see below:
the sum(M(:))-sum(sum(M(2:end-1,2:end-1)))
Thank you.
dpb
am 10 Feb. 2018
Bearbeitet: dpb
am 11 Feb. 2018
Because sum(M(2:end-1,2:end-1)) is a row vector of the sums of the columns in the submatrix; to get the total have to then add those values. This is taken care of in the first sum by the use of the special syntax (:) that returns all elements of an array/matrix in a column so sum only needs to add the one column vector. There is no syntax in Matlab to apply the secondary indexing operation to the result of the first function call return; there've been many suggest the enhancement.
Sanjay Zamindar
am 28 Jun. 2018
Bearbeitet: dpb
am 28 Jun. 2018
function final_sum = peri_sum(A)
size_row = size(A,1)
size_col=size(A,2)
Sum_of_first_row = sum (A(1, [1:1:end])); %base
Sum_of_first_Colmn = sum(A([2:1:size_row],1))
%sum_col= sum(A([2:1:size_col], [1:size_col:size_col]));
Sum_of_last_column= sum(A([2:1:size_row],size_col))
sum_of_last_row = sum(A(size_row,[2:1:size_col-1]))
final_sum = sum_of_last_row+ Sum_of_last_column+Sum_of_first_Colmn+Sum_of_first_row
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!