Reference to a cleared variable seg_result.
Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
Ältere Kommentare anzeigen
Hi friends After I runned the following program: *********************************** clear all; clc; close all;
load('result_3.mat'); load('mouse3.mat'); load('P.mat'); load('b.mat'); Evalue = b; Evector = P;
showcs3(mouse); hold on;
h=[]; h2=[];save_b=[];
location = newkidney; location(:,3) = round(location(:,3));
for k=1:3
[faces,tnorm]=MyRobustCrust(location);
N=ASM_GetContourNormals3D(location,faces);
[gt,dgt]=ASM_getProfileAndDerivatives3D(mouse,location,N,5);
move=zeros(length(location),3);
[C1,I1]=max(abs(dgt));
xi=location(:,1)-N(:,1).*(I1-6)';
yi=location(:,2)-N(:,2).*(I1-6)';
zi=location(:,3)-N(:,3).*(I1-6)';
move=[xi,yi,zi];
if(ishandle(h2)), delete(h2); end
pause(0.5)
h2=plot3(move(:,1),move(:,2),move(:,3),'.r'); drawnow('expose');
move_pos=[move(:,1);move(:,2);move(:,3)];
location1=[location(:,1);location(:,2);location(:,3)];
b =Evector'*(move_pos-location1);
maxb=3*sqrt(Evalue');
b=max(min(b,maxb),-maxb)
xy_search(:,k) = location1 + Evector*b;
save_b=[save_b,b];
pos=[];
pos=xy_search(:,k);
m=length(N);
location=[pos(1:m,1),pos(m+1:2*m,1),pos(2*m+1:3*m,1)];
if(ishandle(h)), delete(h); end
pause(0.5)
h=plot3(location(:,1),location(:,2),location(:,3),'.g');drawnow('expose');
pause(0.5)
end
if(ishandle(h2)), delete(h2); end
figure; I = load('3.txt'); plot3(I(:,1),I(:,2),I(:,3),'.b'); hold on; plot3(location(:,1),location(:,2),location(:,3),'.g');
for l = 153:1:227
figure;
QQ = mouse(:,:,l);
imshow(QQ,[]);
hold on;
seg_result(:, 3) = round(seg_result(:, 3));
for i = 1:1:1519
if seg_result(i, 3) == l
plot(seg_result(i, 2),seg_result(i, 1),'.');
hold on;
end
end
for j = 1:1:1510
if I(j, 3) == l
plot(I(j, 2),I(j, 1),'.r');
end
end
end
***********************************
I saw an error:
Reference to a cleared variable seg_result.
Error in segment (line 70) seg_result(:, 3) = round(seg_result(:, 3));
If you know how to deal with it,please help me.Thank you!
Antworten (0)
Diese Frage ist geschlossen.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!