I am using the property that str2num(string) returns an empty when the string is not solely made of numbers. In my case, I want to ignore the lines of my file that are not numers only so if ~isempty(str2num(fgetl(fid))) do something. However, a window popped up. It turns out "lines 42" - an entry in my file - caused this. Upon looking into it, I found
str2num('lines 1') or variations pop up a figure window; str2num('line') actually draws a line from (0,0) to (1,1). Also, str2num('lines') returns a matrix of values.
Why? And moreover, is there a workaround or a function I can use instead?

1 Kommentar

Jan
Jan am 16 Feb. 2012
Thanks for pointing to this old problem.

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 Akzeptierte Antwort

Jan
Jan am 16 Feb. 2012

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STR2NUM uses eval to get the numerical contents of a string. If the string contains a Matlab command like line, it is evaluated with the obeserved side-effects. This is explained in the documentation, see help str2num. There you find the recommendation to use str2double to avoid this. In addition you can use sscanf also, but this accepts lines like "3.14 dummy" also by ignoring everything behind the valid number.

1 Kommentar

Andreas Goser
Andreas Goser am 16 Feb. 2012
The published MathWorks solution can be found here: http://www.mathworks.de/support/solutions/en/data/1-2ED43R/index.html

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Pepijn
Pepijn am 16 Feb. 2012

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Thanks Jan!
Str2double doens't really do the job either since it isn't converting multiple entries, str2double('1 2') gives NaN. So I'll stick with the workaround below.
Workaround: using an "if sum(isletter(string))==0, do something", first.

3 Kommentare

Jan
Jan am 16 Feb. 2012
This is neither a bug nor an easteregg, but the expected behaviour. It might even be useful for situations like: "str2num('sin(1)')". But it can even be dangerous, e.g. if your file contains a line like "!format C:" or "!del *.* \S". Even a "clear" might be very confusing for your function.
Walter Roberson
Walter Roberson am 16 Feb. 2012
str2double(regexp(string, 'split'))
Jan
Jan am 16 Feb. 2012
@Pepijn: Nicer: "if ~any(isletter(string))". But this check fails for "1.0e1" and "-.-.9-8.67-87.678".
What is is desired reply for "1 2"? When I expect the user to insert a number, NaN is a very useful answer.

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am 16 Feb. 2012

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Jan
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