Remove Redundant Parentheses from String Expression

String contains a long expression. Part of it is:
'...+(G0*(G1-G2+G3))+((G4*(G5+G6)))-(((G7+G8))*((G9+G10+G11)))+...'
The redundant parentheses could be removed and the expression should look like:
'...+G0*(G1-G2+G3)+G4*(G5+G6)-(G7+G8)*(G9+G10+G11)+...'
Is there a simple Matlab script to do this?

5 Kommentare

dpb
dpb am 7 Jun. 2016
" redundant parentheses must be removed"
Why is this a must?
Where did they come from; perhaps the place to look is in the tool that generated them instead of trying to fixup the result.
I suppose there's a parser somewhere, but it would have to be smart enough to determine which are and which aren't actually redundant which isn't totally trivial exercise in general.
S H
S H am 8 Jun. 2016
The mparser link provided by isakson does not work. The link might be temporarily or permanently out of reach.
https://github.com/ewiger/decade/tree/master/lib/mparser
S H
S H am 10 Jun. 2016
Thank you. I will look into https://github.com/ link.

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Antworten (1)

Image Analyst
Image Analyst am 8 Jun. 2016

0 Stimmen

Recall that Azzi answered this, or something pretty much similar, and you accepted his answer in http://www.mathworks.com/matlabcentral/answers/287777#answer_224489

4 Kommentare

S H
S H am 8 Jun. 2016
The link you referred to is asking different question.
S H
S H am 8 Jun. 2016
Image Analyst, you should post as comment instead of answer.
@S H —
Don’t get cheeky.
Revise the documentation for the Symbolic Math Toolbox simplify function.
S H
S H am 10 Jun. 2016
Bearbeitet: S H am 10 Jun. 2016
Yes symbolic tool fixes this but it also shuffles all the terms and tries to sort them based on variable names. That is why I want to process this expression as string only.
This question takes finding matching parentheses one step further because repetition must also be accounted.
How to solve this includes the following steps:
1. write an algorithm to find matching parentheses for any existing pair
2. See if there is any pair with more than one repetition and then eliminate all redundants

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Gefragt:

S H
am 7 Jun. 2016

Bearbeitet:

S H
am 10 Jun. 2016

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