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Save New Variable to the Workspace for every iteration with a 'for' cycle

1 Ansicht (letzte 30 Tage)
Hello all,
I've been trying to save the Q_bar(3x3 matrix) answer seperately for every theta input but I am failing to save the Q_bar answer for each iteration. Because the only output is the final Q_bar matrix.
for theta = [0,45,60,45,45,60,45,0];
m = cos(theta*pi/180);
n = sin(theta*pi/180);
T = [m.^2 n.^2 2*m*n ; n.^2 m.^2 -2*m*n ; -m*n m*n m.^2-n.^2];
Tinv = inv(T);
Q_bar = Tinv*Q*T;
Q_bar = Q_bar(theta);
end
The final output should be Q_bar(0) = [3x3 matrix] , Q_bar(45) = [3x3 matrix], Q_bar(60) = [3x3 matrix] etc.
What can I do?
Thank You already
  3 Kommentare
kerozi
kerozi am 23 Mai 2016
I have thought with another for loop inside should give an answer but it does not.
theta = [0,45,60,45,45,60,45,0];
for i=1:8;
m = cos(theta(i)*pi/180);
n = sin(theta(i)*pi/180);
T = [m.^2 n.^2 2*m*n ; n.^2 m.^2 -2*m*n ; -m*n m*n m.^2-n.^2];
Tinv = inv(T);
Q_bar = Tinv*Q*T;
Q_bar = Q_bar(theta(i));
end
AND I FORGOT TO TELL THAT Q MATRIX IS ALSO 3x3 MATRIX.

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Akzeptierte Antwort

Stephen23
Stephen23 am 23 Mai 2016
Bearbeitet: Stephen23 am 23 Mai 2016
Exactly as Adam said in their comment, just use a 3D array like this:
Q = randi(9,3,3);
vec = [0,45,60,45,45,60,45,0];
out = NaN([size(Q),numel(vec)]);
for k = 1:numel(vec)
theta = vec(k);
m = cos(theta*pi/180);
n = sin(theta*pi/180);
T = [m.^2 n.^2 2*m*n ; n.^2 m.^2 -2*m*n ; -m*n m*n m.^2-n.^2];
Tinv = inv(T);
Q_bar = Tinv*Q*T;
out(:,:,k) = Q_bar;
%Q_bar = Q_bar(theta);
end
But note that you should use \ instead of inv.
  1 Kommentar
kerozi
kerozi am 24 Mai 2016
Thank You, as much as it seems an easy task, it was hard for me to comprehend the overall. But you made it happen. Thank You so much.

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Weitere Antworten (1)

Steven Lord
Steven Lord am 23 Mai 2016
You're trying to create variables like Q_bar0, Q_bar45. etc.? DON'T DO THAT. That would make your code more difficult to read and probably slower. Read this Answer for an explanation.
Adam's suggestion is the recommended approach.
theta = 0:45:360;
M = zeros(3, 3, length(theta));
for k = 1:length(theta)
T = theta(k);
M(:, :, k) = [1 0 0; 0 cosd(T) -sind(T); 0 sind(T) cosd(T)];
end
The rotation matrix for the angle theta(N) [for N between 1 and length(theta)] is M(:, :, N).
And don't use inv, use the backslash operator \ instead.

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