How come this codes works, but the other one doesn't.

1 Ansicht (letzte 30 Tage)
Collin Kerr
Collin Kerr am 5 Mai 2016
Bearbeitet: Stephen23 am 5 Mai 2016
(WORKS) %% variables
V = [17.43 11.46 8.11 4.23 2.29 30.18 19.84 14.05 7.34 3.96 34.85 22.91 16.22 8.47 4.57 13.18 19.84 14.05 7.34 3.96 17.43 11.46 8.11 4.23 2.29];
val = input('Choose a distance between 0 and 36 feet \n');
tmp = abs(V-val);
[xp xp] = min(tmp);
C = V(xp);
%% conditional
if xp <= 25 && xp >=21;
A = 75;
elseif xp <= 20 && xp >=16;
A = 60;
elseif xp <= 15 && xp >=11;
A = 45;
elseif xp <= 10 && xp >=6;
A = 30;
elseif xp <= 5 && xp >=1;
A = 15;
end
if xp == 1|| xp == 6 xp == 11 xp == 16 xp == 21;
M = 1;
elseif xp == 2 xp == 7 xp == 12|| xp == 17|| xp == 22;
M=2;
elseif xp == 3 || xp == 8 || xp == 13 || xp == 18 || xp == 23;
M=3;
elseif xp == 4 xp == 9 xp == 14 xp == 19 xp == 24;
M=4;
elseif xp == 5 || xp == 10 || xp == 15 || xp == 20 || xp == 25;
M =5;
end
if val== 0; M = 1; A = 0; end
%% display
fprintf('The setting that best fits your distance is %0.0f degrees and the %0.0fº string position, which wil give you %0.2f feet', A, M, C);
(DOES NOT WORK)(BELOW)
V = [13.36 12.37 11.36 12.40 10.30 11.43 7.70 9.19 4.60 6.66];
val = input('Choose a distance between 0 and 36 feet \n');
tmp = abs(V-val);
[xp xp] = min(tmp);
C = V(xp);
%% conditional
if xp <= 10 && xp >=9;
A = 75;
elseif xp <=8 && xp >=7;
A = 60;
elseif xp <= 6 && xp >=5;
A = 45;
elseif xp <= 4 && xp >=3;
A = 30;
elseif xp <= 2 && xp >=1;
A = 15;
end
if xp == 1|| xp == 6
M=1;
elseif xp == 2 xp == 7;
M=2;
elseif xp == 3 xp == 8;
M=3;
elseif xp == 4 xp == 9;
M=4;
elseif xp == 5 xp == 10;
M=5;
end
if val== 0; M = 1; A = 0; end
%% display
fprintf('The setting that best fits your distance is %0.0f degrees and the %0.0fº string position, which wil give you %0.2f feet', A, M, C);

Antworten (1)

Image Analyst
Image Analyst am 5 Mai 2016
I've never seen %0.0f and don't know what you're thinking. Just use %f or something without zeros in it. If you want integers, use %d.
  1 Kommentar
Stephen23
Stephen23 am 5 Mai 2016
Bearbeitet: Stephen23 am 5 Mai 2016
I don't know how '%0.0f' could be useful, but '%.0f' can be useful to keep the length of the output correct, e.g. when it should be equal to the number of digits:
>> sprintf('%d',1e19)
ans =
1.000000e+19
>> sprintf('%.0f',1e19)
ans =
10000000000000000000
This is sometimes a more reliable way to count digits than log10 or the like.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Time Series finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by