Find function - index by rows?

For the find function, I noticed that it indexes downward column by column. Is there a way to make it so that it indexes left to right row by row?

1 Kommentar

Stephen23
Stephen23 am 27 Apr. 2016
Nope. Transpose your data and start thinking in terms of columns, not rows.

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Antworten (2)

Azzi Abdelmalek
Azzi Abdelmalek am 27 Apr. 2016

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Apply find function to the transpose of your matrix
find(A'==2) % for example

2 Kommentare

Eric Tran
Eric Tran am 27 Apr. 2016
Is there a way to do it without changing the orientation of the matrix. I'm trying to find the indices for "marching band member positions" and I want to try "moving" members one at a time down a row. With how the find function works now, the members are moving one at a time down a column and I'm running into some issues with that method, so I want to see how doing so with rows would affect my desired output.
Azzi Abdelmalek
Azzi Abdelmalek am 27 Apr. 2016
You are not changing your Matrix, your are just operating on another Matrix which is A'

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Andrei Bobrov
Andrei Bobrov am 27 Apr. 2016
Bearbeitet: Andrei Bobrov am 27 Apr. 2016

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Example:
A = rand(15) > .4; % your array
[i0,j0] = find(A);
c = num2cell(sortrows([i0,j0],1),1);
[i_out,j_out] = c{:};
or jast (as by Azzi)
[j_out,i_out] = find(A.');

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