Help me to solve this code
Ältere Kommentare anzeigen
syms x
L=1;
N=2;
n=N+1;
h=L/N;
for i=1:n
X(1,i)=(i-1)*h;
end
num=1;
den=1;
for j=2:3
num=num.*((x-X(1,j)));
den=den.*(X(1,1)-X(1,j))
end
S(1,1)=num./den;
disp(S(1,1))
1 Kommentar
John D'Errico
am 25 Apr. 2016
Solve what? There is no question here, only some code with no meaning provided behind it.
Antworten (0)
Kategorien
Mehr zu Assumptions finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!