syms x
L=1;
N=2;
n=N+1;
h=L/N;
for i=1:n
X(1,i)=(i-1)*h;
end
num=1;
den=1;
for j=2:3
num=num.*((x-X(1,j)));
den=den.*(X(1,1)-X(1,j))
end
S(1,1)=num./den;
disp(S(1,1))

1 Kommentar

John D'Errico
John D'Errico am 25 Apr. 2016
Solve what? There is no question here, only some code with no meaning provided behind it.

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Gefragt:

am 25 Apr. 2016

Bearbeitet:

am 25 Apr. 2016

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