How to remove rows having repeating elements from a matrix?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Susmita
am 25 Apr. 2016
Kommentiert: David Wagener
am 1 Dez. 2019
If I have a matrix A=[ 1 2 1 4; 1 2 3 4; 3 2 1 4; 3 3 2 1] then I want a matrix as B=[ 1 2 3 4; 3 2 1 4] so that both the 1st and 4th row will be deleted as they have repeated elements. pls help me to find out the code.
0 Kommentare
Akzeptierte Antwort
Roger Stafford
am 25 Apr. 2016
Bearbeitet: Roger Stafford
am 27 Apr. 2016
t = false(1,size(A,1));
for k = 1:size(A,1)
u = unique(A(k,:));
t(k) = size(u,2)==size(A,2);
end
B = A(t,:); % Rows with repeated elements deleted
Weitere Antworten (1)
Baltam
am 25 Apr. 2016
The below method is not elegant but it works.
A=[ 1 2 1 4; 1 2 3 4; 3 2 1 4; 3 3 2 1];
index = zeros(1,size(A,1));
for i = 1:size(A,1)
if numel(unique(A(i,:))) == numel(A(i,:))
index(i)=1;
end
end
index = logical(index);
B = A(index,:);
Kind regards,
Baltam
2 Kommentare
David Wagener
am 1 Dez. 2019
The second version shown here while not as elegant works better if you have a large matrix and are using parallel processing. I'm not an expert by any means but the second version did not overload my machine like the first one did.
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!