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merging two cell type matrix

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sermet
sermet am 21 Apr. 2016
Kommentiert: Andrei Bobrov am 21 Apr. 2016
start_id=[{'p1'};{'p2'};{'p1'};{'p1'};{'p3'}]; %cell
finish_id=[{'p2'};{'p3'};{'p3'};{'p4'};{'p4'}]; %cell
points_id=[{'p1'};{'p2'};{'p3'};{'p4'}]; %cell
m=numel(points_id);
for i=1:m
IndexC_minus(:,i) = strfind(start_id, points_id{i});
IndexC_positive(:,i) = strfind(finish_id, points_id{i});
end
I need to create IndexC_minus_double and IndexC_positive_double matrix as follows;
IndexC_minus_double=[-1 0 0 0;0 -1 0 0;-1 0 0 0;-1 0 0 0;0 0 -1 0]; %for each [1] cell, write -1 numeric and for each [] cell write 0 numeric.
IndexC_positive_double=[0 1 0 0;0 0 1 0;0 0 1 0;0 0 0 1;0 0 0 1]; %for each [1] cell, write 1 numeric and for each [] cell write 0 numeric.
Finally, I need to merge these 2 matrix as below;
merged_matrix=[-1 1 0 0;0 -1 1 0;-1 0 1 0;-1 0 0 1;0 0 -1 1]; % overlapped 0 produces 0 in the merged_matrix. The location of 1 and -1 in the IndexC_minus_double and IndexC_positive_double matrix are the same in the merged_matrix.
  1 Kommentar
Guillaume
Guillaume am 21 Apr. 2016
Did you really mean to use strfind (which will find p1 in abcp1d) and not just compare the strings for equality with strcmp?
You have an odd way of constructing cell arrays. This is simpler:
start_id = {'p1'; 'p2'; 'p1'; 'p1'; 'p3'};

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Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 21 Apr. 2016
Bearbeitet: Andrei Bobrov am 21 Apr. 2016
merged_matrix = bsxfun(@strcmp,finish_id,points_id')...
- bsxfun(@strcmp,start_id,points_id');
ADD
[~,~,c] = unique([start_id;finish_id;points_id]);
ii = zeros(numel(c),1);
n = cellfun(@numel,{start_id;finish_id;points_id});
ii(cumsum(n) - n + 1) = 1;
ii = cumsum(ii);
c3 = c(ii == 3)';
merged_matrix = bsxfun(@eq,c(ii==2),c3) - bsxfun(@eq,c(ii==1),c3)
in your case
v = {start_id;finish_id;points_id};
for ii = 1:3
a = regexp(v{ii},'\d','match');
v{ii} = str2double(cat(1,a{:}));
end
merged_matrix = bsxfun(@eq,v{2},v{3}') - bsxfun(@eq,v{1},v{3}');
other variant
n = numel(points_id);
s = repmat(start_id,1,n);
f = repmat(finish_id,1,n);
nn = repmat(points_id',numel(finish_id),1);
merged_matrix = strcmp(f,nn) - strcmp(s,nn);
  5 Kommentare
sermet
sermet am 21 Apr. 2016
Bearbeitet: sermet am 21 Apr. 2016
Andrei, it gives,
Error using -
Matrix dimensions must agree
merged_matrix = bsxfun(@eq,c(ii==2),c3) - bsxfun(@eq,c(ii==1),c3)
from codes,
bsxfun(@eq,c(ii==2),c3)= []
bsxfun(@eq,c(ii==1),c3)=Empty matrix: 3-by-0
sermet
sermet am 21 Apr. 2016
thank you very much, Andrei.

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Weitere Antworten (1)

Guillaume
Guillaume am 21 Apr. 2016
This is probably much simpler than Andrei's answer. I assume you meant to use strcmp in your original example:
IndexC_minus_double = cell2mat(cellfun(@(s) -strcmp(s, points_id)', start_id, 'UniformOutput', 0))
IndexC_positive = cell2mat(cellfun(@(s) +strcmp(s, points_id)', finish_id, 'UniformOutput', 0))
merged_matrix = IndexC_minus_double + IndexC_positive
Note that I assume that -1 and +1 don't overlap for the merge matrix since you haven't said what happens if this is the case

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