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Syntax Issue in If Statement Using Handles

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Jay
Jay am 11 Apr. 2016
Kommentiert: Jay am 11 Apr. 2016
I am trying to write an if statement in a function, to determine if the handles values are of valid type, as per the stipulation in the texts written above said handles in the GUI.
For handle 'edit1' I have written:
if handles.edit1 == NaN
set(handles.edtit2, 'enable', 'off') && set(handles.listbox1, 'string', 'Date must be of stated syntax')
else set(handles.edit2, 'enable', 'on')
end
During runtime the code skips to else not flagging
if handles.edit1 == Nan
as true thus setting the 'handles.edit2' off and having the error showing in listbox1.
What is wrong with my if statement?

Akzeptierte Antwort

Stephen23
Stephen23 am 11 Apr. 2016
Bearbeitet: Stephen23 am 11 Apr. 2016
You cannot test for equality of NaN's, because as the documentation clearly states, NaN's are not equal to each other. Use isnan instead:
>> handles.edit1 = NaN;
>> handles.edit1 == NaN
ans =
0
>> isnan(handles.edit1)
ans =
1

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 11 Apr. 2016
Use ishghandle() instead testing for NaN .
  1 Kommentar
Jay
Jay am 11 Apr. 2016
Thanks Walter,
I will see if that does what I need.

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