problem with my results

I am plotting a spectrogram using STFT algorithm generated by me everything works fine but my results are not what i expected please help me where I am wrong.
clear all
close all
clc
Fs = 2*max(100,300);
t = 0:1/Fs:1-1/Fs;
t1 = t(end);
x = chirp(t,300,t1,100,'linear');
w = rectwin(10)';
nw= length(w);
X = fft(x);
Total = [];
y = length(x) - nw;
for tau = 0: y
S = 0;
if tau == 0 %1st window
S = X(1:nw);
else %THE remaining windows generated from here
for k = 0:nw-1
for n = 0:nw-1
S= (exp(2*pi*1j*k/nw).*(X(tau : tau + nw-1) - x(tau)+...
x(nw+tau).*exp(-2*pi*1j*n/nw)));
end
end
end
W= S(1:end/2);
Total = [Total; W];
end
%plotting
T = 1:length(x)/2;
imagesc(T,1:Fs/2,20*log10(abs(Total).^2))
axis xy; axis tight; colormap(jet);
xlabel('Time in sec');
ylabel('Frequency (Hz)');

9 Kommentare

Walter Roberson
Walter Roberson am 2 Feb. 2012
The easiest solution would be to change what you are expecting.
We do not know what you are expecting, so there are no code changes we can suggest.
raj
raj am 2 Feb. 2012
i am expecting a spectrogram for a chirp signal using short time fourier transform...
raj
raj am 2 Feb. 2012
the chirp should start from 300 Hz and end at 100 Hz
Walter Roberson
Walter Roberson am 2 Feb. 2012
A chirp that _starts_ at 300 Hz, and _ends_ at 100 Hz? Not 300 to 1000 ? Not 100 to 300 ?
raj
raj am 2 Feb. 2012
I mean to say at t = 0 it starts at 300 Hz and at t(end) it is at 100 Hz
raj
raj am 2 Feb. 2012
I didnt understand your question..
Image Analyst
Image Analyst am 2 Feb. 2012
Chirps increase in frequency as time goes along - the wavelength decreases. See figures in http://en.wikipedia.org/wiki/Chirp_signal .
Walter Roberson
Walter Roberson am 2 Feb. 2012
Looking at that page, they say that down-chirps exist, and it appears that k (rate of increase in frequency) could be negative.
raj
raj am 2 Feb. 2012
My problem is not with chirp signal consider any signal but I am not getting the spectrogram expected please try with a signal of ur own

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Gefragt:

raj
am 2 Feb. 2012

Bearbeitet:

Jon
am 26 Sep. 2013

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