How can I plus (append) string in each loop?
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Yen Hai
am 12 Mär. 2016
Kommentiert: Image Analyst
am 13 Mär. 2016
I have:
person=[1,2];
for i=1:length(person)
if (person(i))== 1
str=sprintf('Person A');
elseif (output(i))==2
str=sprintf('Person B');
elseif (output(i))==3
str=sprintf('Person C');
elseif (output(i))==4
str=sprintf(' Person D');
elseif (output(i))==5
str=sprintf('Person E');
else
str=sprintf('System can not detect!');
end
end
%How can I plus result in each loop, like this:
%str='Person A Person B'
How can I plus result in each loop, like this:
str='Person A Person B'
Thank for your help!
0 Kommentare
Akzeptierte Antwort
Image Analyst
am 12 Mär. 2016
Here's another one of many ways. Not necessarily the best, but along the lines of what you started with. (Is this homework?)
person=[1, 2];
finalString = ''; % Initialize
for i=1:length(person)
if (person(i))== 1
str=sprintf('Person A');
elseif (person(i))==2
str=sprintf('Person B');
elseif (person(i))==3
str=sprintf('Person C');
elseif (person(i))==4
str=sprintf('Person D');
elseif (person(i))==5
str=sprintf('Person E');
else
str=sprintf('System can not detect!');
end
finalString = [finalString, ' ', str]; % Append this string.
end
fprintf('The final string = %s\n', finalString);
2 Kommentare
Image Analyst
am 13 Mär. 2016
Sure, just ask, but remember to attach your images and explain the larger context of what you want.
Weitere Antworten (1)
dpb
am 12 Mär. 2016
Bearbeitet: dpb
am 12 Mär. 2016
I presume output is a typo intending person. But you don't need a loop nor any logical tests at all...
>> people=['A':'Z']; % define population of names from which to pick
>> persons=1:3:8; % chose some arbitrarily
>> sprintf('Person %2c ',people(person))
ans =
Person A Person D Person G
>>
BTW, if don't want the trailing blank or it's a bother, simply wrap with
strtrim(sprintf('Person %2c ',people(person)))
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