Filter löschen
Filter löschen

How to multiply binary image and rgb image in matlab?

12 Ansichten (letzte 30 Tage)
bay rem
bay rem am 3 Mär. 2016
Kommentiert: Sanzhar Askaruly am 31 Okt. 2018
I have a binary image which is the segmented form of another color image . As you know , a binary image is 2-d but an rgb image is 3-d , how want to multiply them together ? i tried this code but an error is generated: function skinCrop(bwSkin,colorSkin)
for i = 1:size(colorImage,1)
for j = 1:size(colorImage,2)
if bwImage(i,j) == 0
colorImage(i,j,:) = 0;
end
end
end
imshow(colorImage);
end
and here there is the error:
Index exceeds matrix dimensions.
  3 Kommentare
bay rem
bay rem am 3 Mär. 2016
its the complete error,thank you, i'll check the sizes
Sanzhar Askaruly
Sanzhar Askaruly am 31 Okt. 2018
I tried your code, it worked, so it seems sizes are the problem.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Image Analyst
Image Analyst am 3 Mär. 2016
There are several ways to do what you want, though bsxfun() is the method I usually use (though it's more cryptic than the .* straightforward method). I first learned that from Sean DeWolski of the Mathworks. However, if bwImage is not the same integer type as colorImage, you will have to modify it.
% Mask the image using bsxfun() function
maskedRgbImage = bsxfun(@times, colorImage, cast(bwImage, 'like', colorImage));
If they're already both the same data type, then having cast in there won't hurt so I always put it in there regardless.

Weitere Antworten (1)

Jan
Jan am 3 Mär. 2016
if both images have the same number of pixels:
result = colorImage .* cat(3, bwImage, bwImage, bwImage);
  7 Kommentare
swathi
swathi am 19 Mär. 2018
Thank you very much sir. It worked. Can I extend me query a little more, if you don mind(Sorry for it). Can I use this code to remove object from all frames in which it(or part of it) is visible? I need some advice, as I am working 1st time on videos. Thanks in advance

Melden Sie sich an, um zu kommentieren.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by